Find the largest of three consecutive whole numbers such that twice the sum of the two smallest numbers is 12 more than three times the largest number.
A)20
B)16
C)17
D)19
E)18

Question

Quizplus · Accepted Answer

Let the three consecutive whole numbers be $x$, $x+1$, and $x+2$. According to the problem, twice the sum of the two smallest numbers is 12 more than three times the largest number. This can be written as:$$2(x + (x+1)) = 3(x+2) + 12$$Simplifying the equation:$$2(2x + 1) = 3x + 6 + 12$$$$4x + 2 = 3x + 18$$$$x = 16$$Therefore, the largest number is $x+2 = 18$.

Find the Largest of Three Consecutive Whole Numbers Such That