Solve the formula $c = \frac { 1 } { 2 } ( B + t ) x$ for the variable $x$ .
A) $x = \frac { B + t } { 2 c }$
B) $x = \frac { c } { 2 ( B + t ) }$
C) $x = \frac { 2 ( B + t ) } { c }$
D) $x = \frac { 2 c } { B + t }$
E) $\chi = \frac { c } { 2 B + 2 t }$

Question

Quizplus · Accepted Answer

To solve for $x$, you need to isolate $x$ on one side of the equation. Starting with $c = \frac { 1 } { 2 } ( B + t ) x$, you can multiply both sides by 2 to get rid of the fraction, resulting in $2c = (B + t)x$. Then, divide both sides by $(B + t)$ to isolate $x$, which gives $x = \frac { 2 c } { B + t }$.

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Solve the Formula $c = \frac { 1 } { 2 } ( B + t ) x$