In general, if L is a sorted list of size n, to determine whether an element is in L, the binary search makes at most 2 * log₂n + 2 key (item) comparisons.

Question

Quizplus · Accepted Answer

The binary search algorithm repeatedly divides the search interval in half. Therefore, the number of key comparisons required is at most log₂n + 1. Since the algorithm also makes one comparison to determine whether the element is in the list, the total number of key comparisons is at most 2 * log₂n + 2.

In General, If L Is a Sorted List of Size