int x = 27;
Int y = 10;do
X = x / 3;
While (x = y);What is the final value of x in the code above?
A) 0
B) 3
C) 9
D) 27

Question

int x = 27;
Int y = 10;do
X = x / 3;
While (x >= y);What is the final value of x in the code above?
A) 0
B) 3
C) 9
D) 27

Quizplus · Accepted Answer

The code uses a do-while loop to repeatedly divide x by 3 as long as x is greater than or equal to y (10 in this case). 
Initial value of x is 27, so in the first iteration of the loop, x becomes 27/3 = 9. 
In the second iteration, x becomes 9/3 = 3. 
In the third iteration, x becomes 3/3 = 1, which is less than y, so the loop exits. 
Therefore, the final value of x is 1.

Option A (0) is incorrect because x can never become 0 with the given code. 
Option B (3) is incorrect because x continues to be divided by 3 until it becomes less than y. 
Option D (27) is incorrect because x is modified inside the loop as explained above.

Int X = 27;