Solve by the elimination method: $$\begin{array} { l }
2 x - 4 y = 6 \
5 x + 5 y = - 15
\end{array}$$
A) (-5, -4)
B) (3, 0)
C) (-1, -2)
D) Dependent
E) No solution

Question

Solve by the elimination method: $$\begin{array} { l } 
2 x - 4 y = 6 \
5 x + 5 y = - 15
\end{array}$$
A) (-5, -4)
B) (3, 0)
C) (-1, -2)
D) Dependent
E) No solution

Quizplus · Accepted Answer

The Answer of Solve by the elimination method: $$\begin{array} { l } 
2 x - 4 y = 6 \
5 x + 5 y = - 15
\end{array}$$
A) (-5, -4)
B) (3, 0)
C) (-1, -2)
D) Dependent
E) No solution

Solve by the Elimination Method 2x−4y=65x+5y=−15\begin{array} { l } 2 x - 4 y = 6 \\5 x + 5 y = - 15\end{array}2x−4y=65x+5y=−15​

Solve by the Elimination Method $\begin{array} { l } 2 x - 4 y = 6 \\5 x + 5 y = - 15\end{array}$