Factor: $6 - 18 z ^ { 2 }$
A) $6 \left( 3 z ^ { 2 } + 1 \right)$
B) $6 \left( z ^ { 2 } + 18 \right)$
C) $6 \left( 3 - z ^ { 2 } \right)$
D) $18 \left( 6 - z ^ { 2 } \right)$
E) $6 \left( 1 - 3 z ^ { 2 } \right)$

Question

Quizplus · Accepted Answer

The correct factorization of $6 - 18z^2$ is $6(1 - 3z^2)$, which is achieved by factoring out the common factor of 6 from both terms.

Factor 6−18z26 - 18 z ^ { 2 }6−18z2 A) 6(3z2+1)6 \left( 3 z ^ { 2 } + 1 \right)6(3z2+1)

Factor $6 - 18 z ^ { 2 }$ A) $6 \left( 3 z ^ { 2 } + 1 \right)$