Factor: $6 z ^ { 3 } - 54 z ^ { 2 } + 108 z$
A) $6 z ( z + 6 ) ( z + 3 )$
B) $z ( 6 z - 36 ) ( z + 3 )$
C) $6 z ( z - 6 ) ( z - 3 )$
D) $6 ( z + 6 ) ( z - 3 )$
E) Nonfactorable over the integers

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is $6z$, giving $6z(z^2 - 9z + 18)$. Factoring the quadratic expression inside the parentheses gives $6z(z - 6)(z - 3)$.

Factor 6z3−54z2+108z6 z ^ { 3 } - 54 z ^ { 2 } + 108 z6z3−54z2+108z

Factor $6 z ^ { 3 } - 54 z ^ { 2 } + 108 z$