Simplify the expression. Assume the denominator is nonzero. $$\frac { ( x - 7 ) ( x + 1 ) } { ( x + 1 ) ( x + 7 ) }$$
A) $\frac { x + 8 } { x + 5 }$
B) $\frac { x - 7 } { x + 7 }$
C) $\frac { x - 8 } { x + 7 }$
D) $\frac { x - 7 } { x + 1 }$
E) $\frac { x + 1 } { x + 7 }$

Question

Quizplus · Accepted Answer

The expression simplifies to $\frac{x-7}{x+7}$ by canceling out the common factor $(x+1)$ in the numerator and denominator.

Simplify the Expression (x−7)(x+1)(x+1)(x+7)\frac { ( x - 7 ) ( x + 1 ) } { ( x + 1 ) ( x + 7 ) }(x+1)(x+7)(x−7)(x+1)​

Simplify the Expression $\frac { ( x - 7 ) ( x + 1 ) } { ( x + 1 ) ( x + 7 ) }$