Simplify: $$\frac { 4 x ^ { 5 } y ^ { 2 } } { 9 x ^ { 3 } y ^ { 4 } }$$
A) $\frac { 9 x ^ { 2 } y ^ { 2 } } { 4 }$
B) $\frac { 4 y ^ { 2 } } { 9 x ^ { 2 } }$
C) $\frac { 4 y ^ { 5 } } { 9 x ^ { 2 } }$
D) $\frac { 4 x ^ { 8 } } { 9 y ^ { 6 } }$
E) $\frac { 4 x ^ { 2 } } { 9 y ^ { 2 } }$

Question

Quizplus · Accepted Answer

To simplify, divide the numerator and denominator by the highest common power of $x$ and $y$. In this case, that is $x^3y^2$:
$$\frac{4x^5y^2}{9x^3y^4} = \frac{4}{9} \cdot \frac{x^5}{x^3} \cdot \frac{1}{y^2}\cdot \frac{1}{y^2} = \boxed{\frac{4x^2}{9y^2}}$$

Simplify 4x5y29x3y4\frac { 4 x ^ { 5 } y ^ { 2 } } { 9 x ^ { 3 } y ^ { 4 } }9x3y44x5y2​

Simplify $\frac { 4 x ^ { 5 } y ^ { 2 } } { 9 x ^ { 3 } y ^ { 4 } }$