Solve the quadratic equation. $( n - 9 ) ^ { 2 } = 3$ Use the following property: For any real number a , $x ^ { 2 } = a$ if and only if $x = \sqrt { a }$ or $x = - \sqrt { a }$ .
A) $\sqrt { 3 } - 9$ , $- \sqrt { 3 } - 9$
B) $\sqrt { 3 } + 9$ , $0$
C) $\sqrt { 3 } + 9$ , $\sqrt { 3 } - 9$
D) $18$ , $0$
E) $\sqrt { 3 } + 9$ , $- \sqrt { 3 } + 9$

Question

Quizplus · Accepted Answer

Given $(n - 9)^2 = 3$, applying the property, $n - 9 = \sqrt{3}$ or $n - 9 = -\sqrt{3}$. Solving for $n$ gives $n = \sqrt{3} + 9$ or $n = -\sqrt{3} + 9$.

Solve the Quadratic Equation (n−9)2=3( n - 9 ) ^ { 2 } = 3(n−9)2=3

Solve the Quadratic Equation $( n - 9 ) ^ { 2 } = 3$