Solve the equation. $x ^ { 3 } - 7 x ^ { 2 } + 12 x = 0$
A)1, 4 , 3
B)0, 4, 3
C)4 , 3
D)-4, -3
E)0, -4 , -3

Question

Quizplus · Accepted Answer

We can factor x out of the equation to obtain the expression: 
$$x(x^2-7x+12)=0$$
From here, we can use the zero product property and set each factor equal to 0:
$$x=0 \quad \text{or} \quad x^2-7x+12=0$$
We can solve the quadratic equation by factoring:
$$x^2-7x+12=(x-3)(x-4)=0$$
So the solutions are: 
$$x=0 \quad \text{or} \quad x=3 \quad \text{or} \quad x=4$$
which matches with choice B.

Solve the Equation x3−7x2+12x=0x ^ { 3 } - 7 x ^ { 2 } + 12 x = 0x3−7x2+12x=0

Solve the Equation $x ^ { 3 } - 7 x ^ { 2 } + 12 x = 0$