Factor the polynomial. $x ^ { 3 } + 8$
A) $( x + 2 ) \left( x ^ { 2 } - 2 x + 4 \right)$
B) $( x - 2 ) \left( x ^ { 2 } - 2 x + 4 \right)$
C) $( x + 2 ) \left( x ^ { 2 } - 2 x - 4 \right)$
D) $( x + 2 ) ^ { 3 }$
E) $( x - 2 ) ^ { 3 }$

Question

Quizplus · Accepted Answer

The polynomial $x^3 + 8$ can be factored using the sum of cubes formula, $a^3 + b^3 = (a + b)(a^2 - ab + b^2)$, where $a = x$ and $b = 2$. This results in $(x + 2)(x^2 - 2x + 4)$.

Factor the Polynomial x3+8x ^ { 3 } + 8x3+8 A) (x+2)(x2−2x+4)( x + 2 ) \left( x ^ { 2 } - 2 x + 4 \right)(x+2)(x2−2x+4)

Factor the Polynomial $x ^ { 3 } + 8$ A) $( x + 2 ) \left( x ^ { 2 } - 2 x + 4 \right)$