Use the factoring method to solve the equation. $$6 x ^ { 2 } + 11 x + 4 = 0$$
A) $- \frac { 4 } { 3 }$ , $- \frac { 1 } { 2 }$
B) $\frac { 1 } { 2 }$ , $\frac { 4 } { 3 }$
C) $- \frac { 1 } { 2 }$ , $\frac { 4 } { 3 }$
D) $- \frac { 4 } { 3 }$ , $\frac { 4 } { 3 }$
E) $- \frac { 4 } { 3 }$ , $\frac { 1 } { 2 }$

Question

Quizplus · Accepted Answer

To factor the quadratic equation $6x^2 + 11x + 4 = 0$, we look for two numbers that multiply to $6 \times 4 = 24$ and add to $11$. These numbers are $8$ and $3$. Thus, we can rewrite the equation as $6x^2 + 8x + 3x + 4 = 0$, which factors into $2x(3x + 4) + 1(3x + 4) = 0$, leading to $(2x + 1)(3x + 4) = 0$. Solving for $x$ gives $x = -\frac{1}{2}$ and $x = -\frac{4}{3}$.

Use the Factoring Method to Solve the Equation 6x2+11x+4=06 x ^ { 2 } + 11 x + 4 = 06x2+11x+4=0

Use the Factoring Method to Solve the Equation $6 x ^ { 2 } + 11 x + 4 = 0$