The perimeter $P$ of a rectangle with length I and width W is given by the formula $P = 2 l + 2 w$ . Solve this formula for W . If the perimeter of a certain rectangle is 46.54 meters and its length is 16.25 meters, find its width.
A) $w = \frac { P - 2 l } { 2 } ; w = 4.83 \mathrm {~m}$
B) $w = \frac { 2 l - P } { 2 } ; w = 7.02 \mathrm {~m}$
C) $w = P - 2 l ; \quad w = 14.04 \mathrm {~m}$
D) $w = \frac { P - 2 l } { 2 } ; w = 7.02 \mathrm {~m}$
E) $w = 2 l - P ; \quad w = 4.83 \mathrm {~m}$

Question

Quizplus · Accepted Answer

We want to solve the formula for W, so we need to isolate W on one side of the equation. Rearranging the equation, we get:
$$P = 2L + 2W$$
$$P - 2L = 2W$$
$$W = \frac{P-2L}{2}$$
Now we can plug in the given values:
$$W = \frac{46.54 - 2(16.25)}{2}$$
$$W = 7.02$$
Therefore, the width is 7.02 meters, and the correct answer is choice D.

The Perimeter PPP Of a Rectangle with Length I and Width W Is

The Perimeter $P$ Of a Rectangle with Length I and Width W Is