The power $P$ lost when an electric current $I$ passes through a resistance $R$ is given by the formula $P = I ^ { 2 } R$ . Solve for $R$ . If $P$ is 2,900 watts and $I$ is 16 amperes, calculate $R$ to the nearest hundredth of an ohm.
A) $R = 11.33 \mathrm { ohms }$
B) $R = 9.28 \text { ohms }$
C) $R = 12.18 \mathrm { ohms }$
D) $R = 181.25 \text { ohms }$
E) $R = 10.18 \mathrm { ohms }$

Question

Quizplus · Accepted Answer

To solve for $R$, we use the formula $P = I^2R$. Rearranging for $R$, we get $R = \frac{P}{I^2}$. Substituting $P = 2900$ watts and $I = 16$ amperes, we find $R = \frac{2900}{16^2} = \frac{2900}{256} = 11.328125$, which rounds to $11.33$ ohms.

The Power PPP Lost When an Electric Current III Passes Through a Resistance

The Power $P$ Lost When an Electric Current $I$ Passes Through a Resistance