Solve the quadratic equation. $n ^ { 2 } - 22 = 0$ Use the following property: For any real number a , $x ^ { 2 } = a$ if and only if $x = \sqrt { a }$ or $x = - \sqrt { a }$ .
A) $\{ \sqrt { 22 } \}$
B) $\{ 11.0 \}$
C) $\{ \sqrt { 22 } , - \sqrt { 22 } \}$
D) $\{ - \sqrt { 22 } \}$
E) $\{ 22,0 \}$

Question

Quizplus · Accepted Answer

To solve the equation, we first isolate the variable term by adding 22 to both sides: $$n^2-22+22=0+22$$ Simplifying the left-hand side gives: $$n^2=22$$ Now we can use the property mentioned in the problem statement: $$n=\sqrt{22} 	ext{ or } n=-\sqrt{22}$$ Therefore, the solution is the set of values: $$\{ \sqrt { 22 } , - \sqrt { 22 } \}$$ which is answer choice C.

Solve the Quadratic Equation n2−22=0n ^ { 2 } - 22 = 0n2−22=0

Solve the Quadratic Equation $n ^ { 2 } - 22 = 0$