Solve the equation. $$\left( 4 ^ { 3 x - 6 } \right) \left( 4 ^ { x + 4 } \right) = 64$$
A) $x = - \frac { 3 } { 4 }$
B) $x = - \frac { 5 } { 4 }$
C) $x = \frac { 5 } { 4 }$
D) $x = \frac { 1 } { 4 }$
E) $x = \frac { 9 } { 4 }$

Question

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The Answer of Solve the equation. $$\left( 4 ^ { 3 x - 6 } \right) \left( 4 ^ { x + 4 } \right) = 64$$
A) $x = - \frac { 3 } { 4 }$
B) $x = - \frac { 5 } { 4 }$
C) $x = \frac { 5 } { 4 }$
D) $x = \frac { 1 } { 4 }$
E) $x = \frac { 9 } { 4 }$

Solve the Equation (43x−6)(4x+4)=64\left( 4 ^ { 3 x - 6 } \right) \left( 4 ^ { x + 4 } \right) = 64(43x−6)(4x+4)=64

Solve the Equation $\left( 4 ^ { 3 x - 6 } \right) \left( 4 ^ { x + 4 } \right) = 64$