In one flip of 10 unbiased coins, what is the probability of getting 8 or more heads?
A) 0.0547
B) 0.0016
C) 0.0439
D) 0.0010

Question

Quizplus · Accepted Answer

The probability of getting exactly 8 heads in 10 flips is calculated using the binomial probability formula, which is $C(n, k) \times p^k \times (1-p)^{n-k}$, where $C(n, k)$ is the combination of n items taken k at a time, $p$ is the probability of success (getting a head), and $n-k$ is the number of failures. For 8 heads, it's $C(10, 8) \times (0.5)^8 \times (0.5)^2$. Similarly, calculate for 9 and 10 heads and add those probabilities together. The sum of these probabilities gives the total probability of getting 8 or more heads out of 10 flips, which is approximately 0.0547.

In One Flip of 10 Unbiased Coins, What Is the Probability