The x - and y -coordinates of a point in quadrant III are consecutive even integers whose product is 48. Find the coordinates of the point.
A) (8, 6)
B) (-8, -6)
C) (-12, -10)
D) (12, 10)

Question

Quizplus · Accepted Answer

Since the two even integers are consecutive, they can be represented as x and x - 2. Therefore, we have x(x - 2) = 48. Expanding the left side, we get x^2 - 2x = 48, which can be rearranged to x^2 - 2x - 48 = 0. Factoring, we have (x - 8)(x + 6) = 0. Since x is a negative even integer (since it is in quadrant III), we have x = -6. Therefore, the point has coordinates (-8, -6).

The X - and Y -Coordinates of a Point in Quadrant