Solve the logarithmic equation. $\log ( 29 x - 1 ) = 1 + \log ( 6 x - 3 )$
A) $x = 29$
B) $x = 31$
C) $x = \frac { 31 } { 29 }$
D) $x = \frac { 29 } { 31 }$

Name: Solve the logarithmic equation. $\log ( 29 x - 1 ) = 1 + \log ( 6 x - 3 )$ A) $x = 29$ B) $x = 31$ C) $x = \frac { 31 } { 29 }$ D) $x = \frac { 29 } { 31 }$
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The Answer of Solve the logarithmic equation. $\log ( 29 x - 1 ) = 1 + \log ( 6 x - 3 )$
A) $x = 29$
B) $x = 31$
C) $x = \frac { 31 } { 29 }$
D) $x = \frac { 29 } { 31 }$

Solve the Logarithmic Equation log⁡(29x−1)=1+log⁡(6x−3)\log ( 29 x - 1 ) = 1 + \log ( 6 x - 3 )log(29x−1)=1+log(6x−3)

Solve the Logarithmic Equation $\log ( 29 x - 1 ) = 1 + \log ( 6 x - 3 )$