Express the following as a single logarithm. (Assume that all variables represent positive real numbers.) $4 \log b x + \frac { 1 } { 2 } \log b ( x - 1 ) - 6 \log _ { b } ( 4 x + 8 )$

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The Answer of Express the following as a single logarithm. (Assume that all variables represent positive real numbers.) $4 \log b x + \frac { 1 } { 2 } \log b ( x - 1 ) - 6 \log _ { b } ( 4 x + 8 )$

Express the Following as a Single Logarithm 4log⁡bx+12log⁡b(x−1)−6log⁡b(4x+8)4 \log b x + \frac { 1 } { 2 } \log b ( x - 1 ) - 6 \log _ { b } ( 4 x + 8 )4logbx+21​logb(x−1)−6logb​(4x+8)

Express the Following as a Single Logarithm $4 \log b x + \frac { 1 } { 2 } \log b ( x - 1 ) - 6 \log _ { b } ( 4 x + 8 )$