Solve the quadratic equation. $8 t ^ { 2 } + 15 = 0$
A) $t = - \frac { \sqrt { 30 } } { 4 } i \text { or } t = \frac { \sqrt { 30 } } { 4 } i$
B) $t = - \frac { \sqrt { 15 } } { 8 } i \text { or } t = \frac { \sqrt { 15 } } { 8 } i$
C) $t = - \frac { \sqrt { 30 } } { 4 } \text { or } t = \frac { \sqrt { 30 } } { 4 }$
D) $t = - \frac { \sqrt { 15 } } { 2 } i \text { or } t = \frac { \sqrt { 15 } } { 2 } i$

Question

Quizplus · Accepted Answer

First, rearrange the equation to $8t^2 = -15$, then solve for $t$ by taking the square root of both sides, resulting in $t = \pm \sqrt{-15/8}$. Simplifying gives $t = \pm \sqrt{15/8}i$, which simplifies further to $t = \pm \frac{\sqrt{30}}{4}i$.

Solve the Quadratic Equation 8t2+15=08 t ^ { 2 } + 15 = 08t2+15=0

Solve the Quadratic Equation $8 t ^ { 2 } + 15 = 0$