Factor the polynomial completely. $9 x ^ { 2 } + 16$
A) $( 3 x + 1 ) ( 3 x - 16 )$
B) $\left( 3 x ^ { 2 } + 4 \right) ( 3 x - 4 )$
C) $( 9 x + 4 ) ( x - 4 )$
D) $( 3 x + 4 ) ( 3 x - 4 )$
E) not factorable

Question

Quizplus · Accepted Answer

The polynomial $9x^2 + 16$ is a sum of squares, which is not factorable over the real numbers.

Factor the Polynomial Completely 9x2+169 x ^ { 2 } + 169x2+16

Factor the Polynomial Completely $9 x ^ { 2 } + 16$