Solve each compound inequality. Express the solution sets in interval notation. Match each compound inequality with the interval to obtain a true statement.
- $( - \infty , 0 ) \cup \left( \frac { 16 } { 15 } , \infty \right)$

Question

Solve each compound inequality. Express the solution sets in interval notation. Match each compound inequality with the interval to obtain a true statement. -$( - \infty , 0 ) \cup \left( \frac { 16 } { 15 } , \infty \right)$ A) $15 x - 14 < 0 \text { and } 13 x - 1 > 0$ B) $x + 1 > 0 \text { and } 13 x - 14 < 0$ C) $13 x + 14 < - 64 \text { or } 13 x + 14 > 13$ D) $15 x - 14 < - 14 \text { or } 15 x - 8 > 8$

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The Answer of Solve each compound inequality. Express the solution sets in interval notation. Match each compound inequality with the interval to obtain a true statement. -$( - \infty , 0 ) \cup \left( \frac { 16 } { 15 } , \infty \right)$ A) $15 x - 14 < 0 \text { and } 13 x - 1 > 0$ B) $x + 1 > 0 \text { and } 13 x - 14 < 0$ C) $13 x + 14 < - 64 \text { or } 13 x + 14 > 13$ D) $15 x - 14 < - 14 \text { or } 15 x - 8 > 8$

Solve Each Compound Inequality (−∞,0)∪(1615,∞)( - \infty , 0 ) \cup \left( \frac { 16 } { 15 } , \infty \right)(−∞,0)∪(1516​,∞)

Solve Each Compound Inequality $( - \infty , 0 ) \cup \left( \frac { 16 } { 15 } , \infty \right)$