Solve the inequality and express the solution sets in interval notation. $\frac { x + 3 } { 16 } - \frac { x + 9 } { 9 } \geq \frac { 7 } { 18 }$
A) $\left[ \frac { - 173 } { 7 } , \infty \right)$
B) $\left( - \infty , \frac { - 173 } { 7 } \right)$
C) $\left( - \infty , \frac { - 173 } { 7 } \right]$
D) $( - \infty , 0 ]$
E) $\left( \frac { - 173 } { 7 } , \frac { - 173 } { 7 } \right)$

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The Answer of Solve the inequality and express the solution sets in interval notation. $\frac { x + 3 } { 16 } - \frac { x + 9 } { 9 } \geq \frac { 7 } { 18 }$
A) $\left[ \frac { - 173 } { 7 } , \infty \right)$
B) $\left( - \infty , \frac { - 173 } { 7 } \right)$
C) $\left( - \infty , \frac { - 173 } { 7 } \right]$
D) $( - \infty , 0 ]$
E) $\left( \frac { - 173 } { 7 } , \frac { - 173 } { 7 } \right)$

Solve the Inequality and Express the Solution Sets in Interval x+316−x+99≥718\frac { x + 3 } { 16 } - \frac { x + 9 } { 9 } \geq \frac { 7 } { 18 }16x+3​−9x+9​≥187​

Solve the Inequality and Express the Solution Sets in Interval $\frac { x + 3 } { 16 } - \frac { x + 9 } { 9 } \geq \frac { 7 } { 18 }$