Solve the equation. $7 y ^ { 2 } + 8 y + 1 = 0$
A) $\left\{ - 1 , - \frac { 1 } { 10 } \right\}$
B) $\left\{ - 1 , - \frac { 1 } { 7 } \right\}$
C) $\left\{ - \frac { 1 } { 11 } , - \frac { 1 } { 7 } \right\}$

Question

Quizplus · Accepted Answer

We can use the quadratic formula to solve for y:
$$y=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$
Plugging in $a=7$, $b=8$, and $c=1$ yields:
$$y=\frac{-8\pm\sqrt{8^2-4(7)(1)}}{2(7)}=\frac{-8\pm\sqrt{36}}{14}=\frac{-8\pm6}{14}$$
So the solutions are $y=-1$ and $y=-\frac{1}{7}$. Therefore, the answer is B, as it lists both solutions.

Solve the Equation 7y2+8y+1=07 y ^ { 2 } + 8 y + 1 = 07y2+8y+1=0

Solve the Equation $7 y ^ { 2 } + 8 y + 1 = 0$