Factor the trinomial completely. $12 y ^ { 2 } + 12 y + 3$
A) (6 y + 3)(2 y $-$ 1)
B) 3 (2 y + 1)(2 y + 1)
C) 3 (2 y $-$ 1)(2 y + 1)
D) 3 (2 y + 1)( y + 1)
E) not factorable

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is 3, to get $3(4y^2 + 4y + 1)$. Then, notice that $4y^2 + 4y + 1$ is a perfect square trinomial, factoring into $(2y + 1)^2$. Thus, the complete factorization is $3(2y + 1)(2y + 1)$.

Factor the Trinomial Completely 12y2+12y+312 y ^ { 2 } + 12 y + 312y2+12y+3

Factor the Trinomial Completely $12 y ^ { 2 } + 12 y + 3$