Factor the following trinomial completely. $y ^ { 2 } - y - 56$
A) ( y + 8)( y $-$ 7)
B) ( y $-$ 8)( y + 7)
C) ( y + 8)( y + 7)
D) y ( y + 1) $-$ 56
E) ( y $-$ 8)( y $-$ 7)

Question

Quizplus · Accepted Answer

The correct factorization of $y^2 - y - 56$ is found by looking for two numbers that multiply to -56 and add to -1. The numbers -8 and 7 fit this criterion, so the trinomial factors as $(y - 8)(y + 7)$.

Factor the Following Trinomial Completely y2−y−56y ^ { 2 } - y - 56y2−y−56

Factor the Following Trinomial Completely $y ^ { 2 } - y - 56$