Use the difference of squares pattern to factor the polynomial. $1 - 9 n ^ { 2 }$
A) (1 $-$ 3 n ) (1 + 3 n )
B) (1 $-$ 3 n ) (1 + 9 n )
C) (1 $-$ 9 n ) (1 + 3 n )
D) (1 $-$ 3 n )
E) none of these

Question

Quizplus · Accepted Answer

The polynomial $1 - 9n^2$ can be factored using the difference of squares formula, $a^2 - b^2 = (a - b)(a + b)$, where $a = 1$ and $b = 3n$, resulting in $(1 - 3n)(1 + 3n)$.

Use the Difference of Squares Pattern to Factor the Polynomial 1−9n21 - 9 n ^ { 2 }1−9n2

Use the Difference of Squares Pattern to Factor the Polynomial $1 - 9 n ^ { 2 }$