Use the elimination-by-addition method to solve the system. $$\left( \begin{array} { c }
16 x - 6 y = - 8 \
12 x + 3 y = - 1
\end{array} \right)$$
A) $\left( \frac { 2 } { 3 } , - \frac { 1 } { 4 } \right)$
B) $\left( - \frac { 1 } { 4 } , \frac { 2 } { 3 } \right)$
C) $\left( \frac { 1 } { 4 } , \frac { 2 } { 3 } \right)$
D) infinitely many solutions
E) no solutions

Question

Use the elimination-by-addition method to solve the system. $$\left( \begin{array} { c } 
16 x - 6 y = - 8 \
12 x + 3 y = - 1
\end{array} \right)$$
A) $\left( \frac { 2 } { 3 } , - \frac { 1 } { 4 } \right)$
B) $\left( - \frac { 1 } { 4 } , \frac { 2 } { 3 } \right)$
C) $\left( \frac { 1 } { 4 } , \frac { 2 } { 3 } \right)$
D) infinitely many solutions
E) no solutions

Quizplus · Accepted Answer

The Answer of Use the elimination-by-addition method to solve the system. $$\left( \begin{array} { c } 
16 x - 6 y = - 8 \
12 x + 3 y = - 1
\end{array} \right)$$
A) $\left( \frac { 2 } { 3 } , - \frac { 1 } { 4 } \right)$
B) $\left( - \frac { 1 } { 4 } , \frac { 2 } { 3 } \right)$
C) $\left( \frac { 1 } { 4 } , \frac { 2 } { 3 } \right)$
D) infinitely many solutions
E) no solutions

Use the Elimination-By-Addition Method to Solve the System (16x−6y=−812x+3y=−1)\left( \begin{array} { c } 16 x - 6 y = - 8 \\12 x + 3 y = - 1\end{array} \right)(16x−6y=−812x+3y=−1​)

Use the Elimination-By-Addition Method to Solve the System $\left( \begin{array} { c } 16 x - 6 y = - 8 \\12 x + 3 y = - 1\end{array} \right)$