Solve the problem by setting up and solving an appropriate inequality. Suppose that the perimeter of a rectangle is to be no greater than 66 inches and the length of the rectangle must be 16 inches. Find the largest possible value for the width of the rectangle.
A) 49 in.
B) 66 in.
C) 34 in.
D) 17 in.

Question

Quizplus · Accepted Answer

The perimeter of a rectangle is given by the formula $P = 2l + 2w$, where $l$ is the length and $w$ is the width. Given that the perimeter must be no greater than 66 inches and the length ($l$) is 16 inches, we can set up the inequality $2(16) + 2w \leq 66$. Simplifying, we get $32 + 2w \leq 66$, which further simplifies to $2w \leq 34$, and finally $w \leq 17$. Therefore, the largest possible value for the width is 17 inches.

Solve the Problem by Setting Up and Solving an Appropriate