Solve the inequality. $10 ( s - 2 )

Name: Solve the inequality. $10 ( s - 2 ) < 12 ( s + 5 )$ A) $( - 40 , \infty )$ B) $( - \infty , - 40 )$ C) $( - \infty , - 35 )$ D) $( - 35 , \infty )$
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Question

Solve the inequality. $10 ( s - 2 ) < 12 ( s + 5 )$
A) $( - 40 , \infty )$
B) $( - \infty , - 40 )$
C) $( - \infty , - 35 )$
D) $( - 35 , \infty )$

Quizplus · Accepted Answer

Expanding both sides of the inequality gives $10s - 20 < 12s + 60$. Subtracting $10s$ and subtracting $60$ from both sides gives $-80 < 2s$, which simplifies to $-40 < s$. This means $s$ is greater than $-40$, which corresponds to the interval $(-40, \infty)$.

Solve the Inequality 10(s−2)<12(s+5)10 ( s - 2 ) < 12 ( s + 5 )10(s−2)<12(s+5)

Solve the Inequality $10 ( s - 2 ) < 12 ( s + 5 )$