Consider the following measurement. $840 \mathrm { lb }$ Find the precision, the greatest possible error, the relative error and the percent of error (to the nearest hundredth of a percent).
A) $10 \mathrm { lb } ; 5 \mathrm { lb } ; 0.005952 ; 0.60 \%$
B) $20 \mathrm { lb } ; 10 \mathrm { lb } ; 0.005952 ; 0.60 \%$
C) $10 \mathrm { lb } ; 10 \mathrm { lb } ; 0.011905 ; 0.60 \%$
D) $10 \mathrm { lb } ; 5 \mathrm { lb } ; 0.011905 ; 1.79 \%$
E) $10 \mathrm { lb } ; 5 \mathrm { lb } ; 0.011905 ; 1.19 \%$

Question

Quizplus · Accepted Answer

The precision of a measurement is determined by the smallest unit to which it is measured. If the measurement is 840 lb without any decimal points, the precision is to the nearest 10 lb, making the greatest possible error 5 lb (half of the precision). The relative error is the greatest possible error divided by the actual measurement: $5 \, \text{lb} / 840 \, \text{lb} = 0.005952$. To find the percent of error, multiply the relative error by 100, resulting in $0.005952 \times 100 = 0.60\%$.

Consider the Following Measurement 840lb840 \mathrm { lb }840lb Find the Precision, the Greatest Possible Error, the Relative Error

Consider the Following Measurement $840 \mathrm { lb }$ Find the Precision, the Greatest Possible Error, the Relative Error