Find the values of a, b and c in the equation. $3 x ^ { 2 } - 16 = 0$
A) a = $16$ , b = $8$ , c = $- 3$
B) a = $3$ , b = 0, c = $- 16$
C) a = $3$ , b = 1, c = $13$
D) a = $3$ , b = 1, c = $- 13$
E) a = $3$ , b = 0, c = $16$

Question

Quizplus · Accepted Answer

We can solve the given quadratic equation by using the quadratic formula: 
$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$
Comparing with the standard form of the quadratic equation $ax^2+bx+c=0$, we can see that in the given equation, $a=3$, $b=0$, and $c=-16$. Substituting these values into the quadratic formula, we get:
$$x=\frac{-0\pm\sqrt{(0)^2-4(3)(-16)}}{2(3)}=\frac{\pm8}{3}$$
Therefore, the correct option is B, with $a=3$, $b=0$, and $c=-16$.

Find the Values of A, B and C in the Equation