Solve graphically. In a concrete mix, there is four times as much gravel as concrete. The total volume is $15 \mathrm { ft } ^ { 3 }$ . How much of each is in the mix if
X = the amount of concrete
Y = the amount of gravel
The equations are $\begin{array} { l }
y = 4 x \
x + y = 15
\end{array}$

Question

Solve graphically. In a concrete mix, there is four times as much gravel as concrete. The total volume is $15 \mathrm { ft } ^ { 3 }$ . How much of each is in the mix if
X = the amount of concrete
Y = the amount of gravel
The equations are $\begin{array} { l } 
y = 4 x \
x + y = 15
\end{array}$

Quizplus · Accepted Answer

The Answer of Solve graphically. In a concrete mix, there is four times as much gravel as concrete. The total volume is $15 \mathrm { ft } ^ { 3 }$ . How much of each is in the mix if
X = the amount of concrete
Y = the amount of gravel
The equations are $\begin{array} { l } 
y = 4 x \
x + y = 15
\end{array}$

Solve Graphically 15ft315 \mathrm { ft } ^ { 3 }15ft3

Solve Graphically $15 \mathrm { ft } ^ { 3 }$