Find the weight of a cement floor that is $16$ ft by $13$ ft by $3$ ft, if $1 \mathrm { ft }$ ³ of cement weighs $197$ lb. A) 40,976 pounds B) 122,928 pounds C) 9,456 pounds D) 1,233,353 pounds E) 116,230 pounds

Question

Quizplus · Accepted Answer

The volume of the cement floor is $16	ext{ ft} \cdot 13	ext{ ft} \cdot 3	ext{ ft} = 624	ext{ ft}^3$. Since each cubic foot of cement weighs 197 pounds, the total weight is $197	ext{ lb/ft}^3 \cdot 624	ext{ ft}^3 = 122\comma 928	ext{ pounds}$. Therefore, the answer is choice $\boxed{	extbf{(B)}}$.

Find the Weight of a Cement Floor That Is 161616 Ft By

Find the Weight of a Cement Floor That Is $16$ Ft By