Factor completely. Check by multiplying the factors. $49 x ^ { 2 } - 25$
A) $( 7 x + 5 ) ( 7 x + 5 )$
B) $( 7 x - 5 ) ( 7 x + 5 )$
C) $( x - 5 ) ( 49 x + 5 )$
D) $( 7 x - 25 ) ( 7 x + 1 )$
E) $( 49 x - 5 ) ( x + 5 )$

Question

Quizplus · Accepted Answer

This expression is a difference of squares, which factors into $(7x-5)(7x+5)$. It can be checked by using the distributive property to multiply the factors together and verifying that it results in the original expression.

Factor Completely 49x2−2549 x ^ { 2 } - 2549x2−25 A) (7x+5)(7x+5)( 7 x + 5 ) ( 7 x + 5 )(7x+5)(7x+5)

Factor Completely $49 x ^ { 2 } - 25$ A) $( 7 x + 5 ) ( 7 x + 5 )$