Use an algebraic approach to solve the problem. Find three consecutive integers whose sum is 48.
A) -15, -16, -17
B) 15, 14, 13
C) 17, 18, 19
D) 20, 21, 22
E) 15, 16, 17

Question

Quizplus · Accepted Answer

Let the first integer be $x$, the second $x+1$, and the third $x+2$. The sum is $x + (x+1) + (x+2) = 48$. Simplifying, $3x + 3 = 48$, so $3x = 45$, and $x = 15$. Therefore, the integers are 15, 16, and 17.

Use an Algebraic Approach to Solve the Problem