Compare the graph of $f ( x ) = e ^ { x } + 7$ to the graph of $f ( x ) = e ^ { x }$ .
A) The graph of $f ( x ) = e ^ { x } + 7$ is 7 units above the graph of $f ( x ) = e ^ { x }$ .
B) The graph of $f ( x ) = e ^ { x } + 7$ is 7 units below the graph of $f ( x ) = e ^ { x }$ .
C) The graph of $f ( x ) = e ^ { x } + 7$ is 7 units to the right of $f ( x ) = e ^ { x }$ .
D) The graph of $f ( x ) = e ^ { x } + 7$ is 7 units to the left of $f ( x ) = e ^ { x }$ .

Question

Quizplus · Accepted Answer

Adding 7 to the function $f(x) = e^x$ shifts its graph vertically upwards by 7 units, resulting in the graph of $f(x) = e^x + 7$ being 7 units above the original graph. Horizontal shifts are caused by changes inside the function argument (x), not by adding or subtracting constants outside the function.

Compare the Graph Of f(x)=ex+7f ( x ) = e ^ { x } + 7f(x)=ex+7

Compare the Graph Of $f ( x ) = e ^ { x } + 7$