Solve $6 x ^ { 2 } + 12 x + 5 = 0$ by the quadratic formula.
A) $\left\{ \frac { - 6 \pm \sqrt { 6 } } { 6 } \right\}$
B) $\{ - 1 \pm \sqrt { 6 } \}$
C) $\left\{ \frac { 6 \pm \sqrt { 6 } } { 6 } \right\}$
D) $\{ \pm \sqrt { 6 } \}$

Question

Quizplus · Accepted Answer

The quadratic formula is $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$. For $6x^2 + 12x + 5 = 0$, $a = 6$, $b = 12$, and $c = 5$. Plugging these into the formula gives $x = \frac{-12 \pm \sqrt{(12)^2 - 4(6)(5)}}{2(6)} = \frac{-12 \pm \sqrt{144 - 120}}{12} = \frac{-12 \pm \sqrt{24}}{12} = \frac{-12 \pm 2\sqrt{6}}{12} = \frac{-6 \pm \sqrt{6}}{6}$.

Solve 6x2+12x+5=06 x ^ { 2 } + 12 x + 5 = 06x2+12x+5=0

Solve $6 x ^ { 2 } + 12 x + 5 = 0$