Find the domain and range of the function $f ( x )$ . $f ( x ) = \sqrt { x } + 1$
A) $D = [ 0 , \infty ) ; R = [ - 2 , \infty )$
B) $D = [ - \infty , - 2 ) ; R = ( - \infty , \infty )$
C) $D = [ 0 , \infty ) ; R = ( 1 , \infty )$
D) $D = [ - \infty , - 2 ) ; R = ( - 2 , \infty )$
E) $D = [ 0 , \infty ) ; R = [ 1 , \infty )$

Question

Quizplus · Accepted Answer

The domain of $f(x) = \sqrt{x} + 1$ is $D = [0, \infty)$ because the square root function is defined for $x \geq 0$. The range is $R = [1, \infty)$ because the smallest value of $f(x)$ is 1 (when $x = 0$), and it increases without bound as $x$ increases.

Find the Domain and Range of the Function f(x)f ( x )f(x)

Find the Domain and Range of the Function $f ( x )$