Divide using long division: $\frac { 9 x ^ { 3 } + 3 x ^ { 2 } + 6 x - 6 } { 3 x - 2 }$
A) $3 x ^ { 2 } + 3 x + 4 + \frac { 2 } { 3 x - 2 }$
B) $3 x ^ { 2 } + 3 x + 4 - \frac { 14 } { 3 x - 2 }$
C) $3 x ^ { 2 } - x + 2 - \frac { 2 } { 3 x - 2 }$
D) $3 x ^ { 2 } - x + 2 - \frac { 10 } { 3 x - 2 }$

Question

Quizplus · Accepted Answer

Dividing $9x^3 + 3x^2 + 6x - 6$ by $3x - 2$, the quotient is $3x^2 + x + 2$ and the remainder is $4$, so the complete division is $3x^2 + x + 2 + \frac{4}{3x - 2}$. However, there was a mistake in my calculation. Correctly, the quotient is $3x^2 + 3x + 4$ and the remainder is $2$, leading to the correct answer $3x^2 + 3x + 4 + \frac{2}{3x - 2}$.

Divide Using Long Division 9x3+3x2+6x−63x−2\frac { 9 x ^ { 3 } + 3 x ^ { 2 } + 6 x - 6 } { 3 x - 2 }3x−29x3+3x2+6x−6​

Divide Using Long Division $\frac { 9 x ^ { 3 } + 3 x ^ { 2 } + 6 x - 6 } { 3 x - 2 }$