Factor completely: $3 x ^ { 4 } - 48$
A) $3 ( x - 2 ) ( x + 2 ) \left( x ^ { 2 } + 4 \right)$
B) $3 ( x - 2 ) ( x + 2 ) ^ { 2 }$
C) $3 \left( x ^ { 2 } - 4 \right) \left( x ^ { 2 } + 4 \right)$
D) $3 \left( x ^ { 4 } - 16 \right)$

Question

Quizplus · Accepted Answer

We can first factor out a 3: 
$$3\left(x^4-16\right)$$
Then, we can use the difference of squares to factor further: 
$$3\left(x^2-4\right)\left(x^2+4\right)$$
And finally, we can use the difference of squares again to get: 
$$3(x-2)(x+2)(x^2+4)$$
Therefore, the correct choice is A.

Factor Completely 3x4−483 x ^ { 4 } - 483x4−48 A) 3(x−2)(x+2)(x2+4)3 ( x - 2 ) ( x + 2 ) \left( x ^ { 2 } + 4 \right)3(x−2)(x+2)(x2+4)

Factor Completely $3 x ^ { 4 } - 48$ A) $3 ( x - 2 ) ( x + 2 ) \left( x ^ { 2 } + 4 \right)$