Solve the inequality: $- 2

Question

Solve the inequality: $- 2 < \frac { 5 x - 3 } { - 3 } < 3$
A) $\left( - \frac { 3 } { 5 } , 0 \right)$
B) $\left( \frac { 9 } { 5 } , - \frac { 6 } { 5 } \right)$
C) $\left( - \frac { 3 } { 5 } , \frac { 12 } { 5 } \right)$
D) $\left( - \frac { 6 } { 5 } , \frac { 9 } { 5 } \right)$

Quizplus · Accepted Answer

To solve the inequality $-2 < \frac{5x - 3}{-3} < 3$, multiply all parts by -3 (remember to flip the inequality signs because we're multiplying by a negative number): $6 > 5x - 3 > -9$. Then, add 3 to all parts: $9 > 5x > -6$. Finally, divide by 5: $\frac{9}{5} > x > -\frac{6}{5}$, which corresponds to the interval $\left( -\frac{6}{5}, \frac{9}{5} \right)$.

Solve the Inequality −2<5x−3−3<3- 2 < \frac { 5 x - 3 } { - 3 } < 3−2<−35x−3​<3

Solve the Inequality $- 2 < \frac { 5 x - 3 } { - 3 } < 3$