Solve: $7 x - 1 \geq 6$ or $\frac { x } { 6 } + 5

Name: Solve: $7 x - 1 \geq 6$ or $\frac { x } { 6 } + 5 < 4$ A) $( - 6,1 ]$ B) $[ - 1 , \infty )$ C) $( - \infty , - 6 ) \cup [ 1 , \infty )$ D) $( - \infty , - 6 )$
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Question

Solve: $7 x - 1 \geq 6$ or $\frac { x } { 6 } + 5 < 4$
A) $( - 6,1 ]$
B) $[ - 1 , \infty )$
C) $( - \infty , - 6 ) \cup [ 1 , \infty )$
D) $( - \infty , - 6 )$

Quizplus · Accepted Answer

For the first inequality, we add 1 to both sides and divide by 7 to get $x\geq 1$.
For the second inequality, we subtract 5 from both sides and multiply by 6 to get $x<-6$.
Therefore, the solution is the union of these two inequalities, which is $( - \infty , - 6 ) \cup [ 1 , \infty )$.

Solve 7x−1≥67 x - 1 \geq 67x−1≥6 Or x6+5<4\frac { x } { 6 } + 5 < 46x​+5<4

Solve $7 x - 1 \geq 6$ Or $\frac { x } { 6 } + 5 < 4$