A total of $25,000 was invested in two accounts for one year and the amount earned was $1,550. Part of the money was invested at 6% and the rest at 7%. Write a system of two equations in two unknowns that would model the situation. Let x = amount invested at 6% and y = amount invested at 7%.
A) $\left\{ \begin{array} { l }
x + y = 1,550 \
.06 x + .07 y = 25,000
\end{array} \right.$
B) $\left\{ \begin{array} { l }
x + y = 25,000 \
.6 x + 7 y = 1,550
\end{array} \right.$
C) $\left\{ \begin{array} { l }
x + y = 1,550 \
.6 x + 7 y = 25,000
\end{array} \right.$
D) $\left\{ \begin{array} { l }
x + y = 25,000 \
.06 x + .07 y = 1,550
\end{array} \right.$

Question

A total of $25,000 was invested in two accounts for one year and the amount earned was $1,550. Part of the money was invested at 6% and the rest at 7%. Write a system of two equations in two unknowns that would model the situation. Let x = amount invested at 6% and y = amount invested at 7%.
A) $\left\{ \begin{array} { l } 
x + y = 1,550 \
.06 x + .07 y = 25,000
\end{array} \right.$
B) $\left\{ \begin{array} { l } 
x + y = 25,000 \
.6 x + 7 y = 1,550
\end{array} \right.$
C) $\left\{ \begin{array} { l } 
x + y = 1,550 \
.6 x + 7 y = 25,000
\end{array} \right.$
D) $\left\{ \begin{array} { l } 
x + y = 25,000 \
.06 x + .07 y = 1,550
\end{array} \right.$

Quizplus · Accepted Answer

We know that the total investment amount is $25,000, so the first equation should be x + y = 25,000. The amount earned from the investment is $1,550, so the second equation should be .06x + .07y = 1,550. Thus, the correct choice is D.

A Total of $25,000 Was Invested in Two Accounts for One