Solve the system. To do so, substitute $a + b i$ for $- 3 i ( 6 - 6 i )$ and $- 10 - 10 i$ for $14 - 14 i$ and solve for $16 - 16 i$ and $- 12 + 12 i$ . Then find $- 18 - 18 i$ and $- 3$ using the fact that and . $\varnothing$
B) $( 5,6 )$
C) $( - 5,6 )$
D) $( - 5 , - 6 )$
E) $( - 6 , - 5 )$

Question

Solve the system. To do so, substitute $a + b i$ for $- 3 i ( 6 - 6 i )$ and $- 10 - 10 i$ for $14 - 14 i$ and solve for $16 - 16 i$ and $- 12 + 12 i$ . Then find $- 18 - 18 i$ and $- 3$ using the fact that  and  . $\varnothing$
B) $( 5,6 )$ 
C) $( - 5,6 )$ 
D) $( - 5 , - 6 )$ 
E) $( - 6 , - 5 )$

Quizplus · Accepted Answer

The Answer of Solve the system. To do so, substitute $a + b i$ for $- 3 i ( 6 - 6 i )$ and $- 10 - 10 i$ for $14 - 14 i$ and solve for $16 - 16 i$ and $- 12 + 12 i$ . Then find $- 18 - 18 i$ and $- 3$ using the fact that  and  . $\varnothing$
B) $( 5,6 )$ 
C) $( - 5,6 )$ 
D) $( - 5 , - 6 )$ 
E) $( - 6 , - 5 )$

Solve the System a+bia + b ia+bi For −3i(6−6i)- 3 i ( 6 - 6 i )−3i(6−6i)

Solve the System $a + b i$ For $- 3 i ( 6 - 6 i )$