Find the vertices for $\frac { y ^ { 2 } } { 4 } - \frac { x ^ { 2 } } { 16 } = 1$ .
A) $( 2,0 )$ ; $( - 2,0 )$
B) $( 0,2 )$ ; $( 0 , - 2 )$
C) $( 0,4 )$ ; $( 0 , - 4 )$
D) $( 4,0 )$ ; $( - 4,0 )$

Question

Quizplus · Accepted Answer

The given equation is of a hyperbola centered at the origin. The vertices are located at the ends of the major axis, which, for this equation, is along the y-axis. The length of the semi-major axis is the square root of the denominator under $y^2$, which is 2. Therefore, the vertices are $(0,2)$ and $(0,-2)$.

Find the Vertices For y24−x216=1\frac { y ^ { 2 } } { 4 } - \frac { x ^ { 2 } } { 16 } = 14y2​−16x2​=1

Find the Vertices For $\frac { y ^ { 2 } } { 4 } - \frac { x ^ { 2 } } { 16 } = 1$