One mole of HI is placed in a 5.00 L container at 458 C. If K c = 2.06 10 - 2 at the reaction temperature, what is the equilibrium concentration of I2 (g) ?
2 HI (g)
H₂ (g) + I2 (g)
A) 0.112 M
B) 9.33×10 - 2 M
C) 2.06×10 - 2 M
D) 2.33×10 - 2 M
E) 0.467 M
Correct Answer:
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