Given the equation below, what is D H for burning 2.00 g of CO (g) in excess oxygen?
2 CO (g) + O₂ (g) →2 CO₂ (g) D H = - 566 kJ

Question

Given the equation below, what is D H for burning 2.00 g of CO (g) in excess oxygen? 2 CO (g) + O₂ (g)→2 CO₂ (g) D H = - 566 kJ

Quizplus · Accepted Answer

According to the equation, 2 moles of CO reacts to form 2 moles of COS and releases 566 kJ of heat. We can use the molar mass of CO (28.01 g/mol) to calculate the number of moles in 2.00 g of CO, which is approximately 0.071 moles. Since 2 moles of CO release 566 kJ of heat, 0.071 moles of CO will release (566 kJ/2 mol) x 0.071 mol = 20.1 kJ of heat. However, since the question asks for the enthalpy change when burning CO, the sign of the answer must be negative. Therefore, the enthalpy change is -20.1 kJ, which is closest to choice C (-20.2 kJ).

Given the Equation Below, What Is D H for Burning